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Edexcel | Physics WPH0 | W 12 6 1 | 1 hour 30 minutes
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  • Q1
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  • Q3
  • Q4
1
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The spring shown below is made up of loops of wire. There are two extra loops on each

end.

A student wants to determine the total length of wire used to make the spring.

She only has digital callipers.

She decides to find the length of wire, l, in each loop and multiply this by the total

number of loops.

1
(a)
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She obtains the following values for d.

1
(a) (I)
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1 Mark

Use these values to calculate a mean value for d.

mean value for d = 15.52 or 15.5 (mm) 3/4 SF and no u.p.

1
(a) (II)
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Hence calculate a value for l.

l = 48.76 or 48.69 mm to 3/4 SF allow ecf

1
(a) (III)
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Estimate the percentage uncertainty in your value for l.

Calculates percentage uncertainty in d (this is the same as the %U in l)

Half range is 0.04 mm assume this as uncertainty in d. Ignore SF allow ecf

(Allow whole range for 0.6 %,)

Example of calculation

%U = 0.04/15.52 = 0.3 %

1
(b)
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There are 30.5 loops in the main part of the spring. At both ends of the spring there

are 2 extra loops. These loops are the same size as the main ones.

1
(b) (I)
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Calculate the total length of wire in the spring.

l = 1682 mm to 3/4 SF

Example of calculation

48.76 x 34.5 = 1682 mm (accept 1680) allow ecf on d

1
(b) (II)
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1 Mark

The student forgets the 2 extra loops at both ends.

Estimate the percentage uncertainty in her value for the total length of wire

caused by this error.

%U = 11.6%

(allow 2 in 32.5 (6.15%))

Example of calculation

Error is 4 coils in 34.5 ie 4/34.5

1
(c)
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2 Mark s

She now wants to measure the diameter of the wire that makes the spring.

Describe how you would do this as accurately as possible.

Measure the coiled length of spring with callipers and divide by the number of

loops (do not credit use of micrometer screw gauge)

Sensible precaution for their choice of instrument

eg repeat and average

measure in different places/orientations

  • Q1
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  • Q4

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