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Edexcel | Physics WPH0 | S 12 6 1 | 1 hour 30 minutes
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  • Q1
  • Q2
  • Q3
  • Q4
1
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A shallow tray holds water. The depth d of the water is about 2 cm.

1
(a) (I)
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1 Mark

Describe how you would measure d to a precision of 1 mm.

Use a metre rule in a number of places or other valid comment

1
(a) (II)
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1 Mark

Estimate the percentage uncertainty in this measurement.

(100 × 1/20 = ) 5%

1
(b)
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2 Mark s

One side of the tray is lifted up 2 cm and dropped. This causes a wave to cross the

surface of the water. The wave is reflected from side to side across the surface.

The wave takes a time t to cross the surface once.

Describe how you would determine an accurate value for t.

Measure the time for more than one cross at a time (not one cross a

number of times)

Repeat and find mean

1
(c)
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A student measures the distance across the tray as 33.4 cm with an uncertainty of 0.2 cm.

She then determines t = 0.92 s with an uncertainty of 0.03 s.

1
(c) (I)
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1 Mark

Use these measurements to calculate v, the velocity of the wave.

1
(c) (II)
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2 Mark s

Estimate the percentage uncertainty in your value for v.

Calculates %U for distance or time correctly

adds both correct %U - no SF penalty

Example of calculation

100 × (2/334 + 3/92) = 0.6 + 3.3 = 3.9%, accept 3.86% and 4%

1
(d)
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The student is told that

                                    

where k is a constant.

1
(d) (I)
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1 Mark

She measures the depth d as 2.1 cm. Calculate a value for k.

Correct calculation for speed squared divided by 0.021 m

                                                   – 2/3 SF but ignore unit

Example of calculation

1
(d) (II)
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1 Mark

Use your previous answers to estimate the percentage uncertainty in k.

Doubles %U in v (c(ii)) and adds to %U in d (a(ii))

Example of calculation

(3.9 × 2) + 5 = 12.8% allow ecf on their values

1
(e)
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2 Mark s

It is suggested that the value for k is equal to the strength of the Earth’s gravitational

Use your calculations to discuss whether these results support the suggestion.

Calculates % Difference, must use 9.81 as denominator

eg %D is 100 × ((9.81 – 6.27)/9.81) = 36%

Or

uses uncertainty to calculate likely maximum value for k

Makes valid comment based on comparison of data

eg                   %D > %U so k ≠ g

or                    7.11 < 9.81 so k ≠ g

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  • Q4

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